In the triangle abc ,D and E are points on sides AB and AC respectively such that de is parallel to bc if AE = 20cm, AD = 3 cm and BD = 4.5 cm, then find CE.
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Answer:
AC=8.8 cm
Explanation:
In ΔABC, D and E are the points on sides AB and AC respectively such that DE parallel to BC as shown in attach figure.
AD:DB=3:1 or
If EA=6.6 cm
Using Basic proportionality theorem, In a triangle a line is drawn parallel to one side of a triangle and intersect the other two side at distinct points, the other two sides are divided in the same ratio.
Substitute the value of AD:DB and AE. We get
EC=2.2 cm
We need to find length of AC.
AC=AE+EC
AC=6.6+2.2
AC=8.8 cm
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