In the triangle abc ,D and E are points on sides AB and AC respectively such that de is parallel to bc if AE = 20cm, AD = 3 cm and BD = 4.5 cm, then find CE.
Answers
Answered by
5
Step-by-step explanation:
AD/DB=AE/EC
3cm/4.5cm=20cm/CE
3cmCE=4.5cm×20cm
CE=90/3
CE=30cm
Answered by
2
Given : in ΔABC , D and E are points on sides AB and AC respectively such that de is parallel to bc
AE = 20cm, AD = 3 cm and BD = 4.5 cm,
To Find CE.
Solution:
Thales's theorem :
If a straight line is drawn parallel to a side of a triangle, then it divides the other two sides proportionately.
Its also called BPT : Basic proportionality theorem.
DE || BC
Using thales theorem ( BPT)
AD/BD = AE/CE
=> 3/4.5 = 20/CE
=> 3CE = 90
=> CE = 30 cm
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