in the triangle ABC given below, Z is the mid point of the median AD . if the area of triangle ABC is 18 meter square.find the area of triangle BZC
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In ΔABC, Z is the mid-point of the median AD
Join Z to B and C
Therefore, it will divide ΔABC into two triangles of equal area.
∴A(ΔBZD)=A(ΔBZA)
⇒A(ΔBZD)= 1/2 A(ΔABD)...............(i)
Also, A(ΔDZC)=A(ΔAZC)
⇒A(ΔDZC)= 1/2 A(ΔADC)......................(ii)
A(ΔBZD)+A(ΔDZC)= 1/2A(ΔABD)
+ 1/2 A(ΔADC)
A(ΔBZC)= 1/2 A(ΔABC)=
1/2 ×18=9m²
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Hope it will help you...
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