in the triangle abc similar to triangle ade. if ad:db=2:3 and de=5cm. 1) fnd bc. 2) if x be the length of the perpendicular from a to be , find the length of the perpendicular from a to bc in terms of x
Answers
Given : ΔADE ≈ ΔABC . ad:db=2:3 and de=5cm. x be the length of the perpendicular from a to de
To find : BC & length of the perpendicular from a to bc in terms of x
Solution:
ΔADE ≈ ΔABC
=> AD/AB = DE/BC
=> AD/(AD + DB) = DE/BC
=> 2/(2 + 3) = 5/BC
=> BC = 25/2
=> BC = 12.5 cm
as ΔADE ≈ ΔABC
=> Their corresponding altitude will be in the same ratio as sides
hence
AD/AB = length of the perpendicular from a to de/length of the perpendicular from a to bc
=> 2/5 = x/length of the perpendicular from a to bc
=> length of the perpendicular from a to bc = 5x/2
BC = 12.5 cm
length of the perpendicular from a to bc = 5x/2
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Given : ΔADE ≈ ΔABC . ad:db=2:3 and de=5cm. x be the length of the perpendicular from a to de
To find : BC & length of the perpendicular from a to bc in terms of x
Solution:
ΔADE ≈ ΔABC
=> AD/AB = DE/BC
=> AD/(AD + DB) = DE/BC
=> 2/(2 + 3) = 5/BC
=> BC = 25/2
=> BC = 12.5 cm
as ΔADE ≈ ΔABC
=> Their corresponding altitude will be in the same ratio as sides
hence
AD/AB = length of the perpendicular from a to de/length of the perpendicular from a to bc
=> 2/5 = x/length of the perpendicular from a to bc
=> length of the perpendicular from a to bc = 5x/2
BC = 12.5 cm
length of the perpendicular from a to bc = 5x/2