In the triangle ABCprove that sin A+B/2 =cos C/2
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Answer:
L.H.S. =
4sin(A/2)sin(B/2)sin(C/2)
4sinAsinBsinC
=8cos(A/2)cos(B/2)cos(C/2) ∵sinA=2sin(A/2)cos(A/2) etc
Answered by
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Answer:
a+b/2=cos c/2
Step-by-step explanation:
a+b/2=<cosc/2
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