In the triangle angle ABC ,A is greater than B of 24 degree, outside angle of C is 108 then find angle of A?
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Answered by
0
let angle B=x,
then
angle A=x+24°,
now according to question,we have
exterior angle C = interior angle A + interior angle B,
108°=x+24°+x,
108°-24°=2x,
84°=2x,
then
x=42°,
therefore
angle B=42°,
angle A=42°+24°=66°
then
angle A=x+24°,
now according to question,we have
exterior angle C = interior angle A + interior angle B,
108°=x+24°+x,
108°-24°=2x,
84°=2x,
then
x=42°,
therefore
angle B=42°,
angle A=42°+24°=66°
Answered by
0
let angle B=x,
then
angle A=x+24°,
now according to question,we have
exterior angle C = interior angle A + interior angle B,
108°=x+24°+x,
108°-24°=2x,
84°=2x,
then
x=42°,
therefore
angle B=42°,
angle A=42°+24°=66°
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