Question

In the triangle NOW, NO= 40cm, OW= 9cm and NW= 41cm. find the degree measure of ∟O. (with process)​

Answer 1

Answer:

That is

{a}^{2} + {b}^{2} = {c}^{2}a2+b2=c2

However, using this above rule we are going to solve this question.

Now ,

Let's take any two numbers in place of a and b and remaining number in place of c

That is,

\begin{gathered}(9 {)}^{2} + (40 {)}^{2} =( 41 {)}^{2} \\ 81 + 1600 \: \: \: \: = 1681 \\ 1681 = 1681 \\ hence \: solved\end{gathered}(9)2+(40)2=(41)281+1600=16811681=1681hencesolved

And finally,

The pythagoran triplet rule was been satisfied.

Conclusion:

Since the measurements are obeying the rule of pythagoran triplet.

Hence,

This rule also satisfies pythagoran theorem.

So therefore,

The triangle is a right angled triangle.