In the triangle PQR, AB//QR. The ratio of areas of two similar PAB and PQR is 1:2.Then PQ/AQ=
Answers
Answered by
26
here's Ur answer. mark it as brainliest...
Attachments:
Answered by
33
Hi friend,
Here is your answer,
_____________________________________________________________
P
/\
/ \
A / \ B
/ \
/ \
Q / \ R
∠ PAB = ∠ PAQ (corresponding angles)
∠ PBA = ∠ PRQ ( " )
Δ PAB ≈ ΔPQR
PQ² = PR² = QR² = ar(ΔPAB)
PA² PB² AB² ar(ΔPQR)
PQ² = 1
PA² 2
PQ = 1
PA √2
PQ -1 = 1 - √2
PA √2
PQ-PA = 1 - √2
PA √2
AQ = 1 - √2
PQ √2
PQ = √2
AQ 1 - √2
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
Here is your answer,
_____________________________________________________________
P
/\
/ \
A / \ B
/ \
/ \
Q / \ R
∠ PAB = ∠ PAQ (corresponding angles)
∠ PBA = ∠ PRQ ( " )
Δ PAB ≈ ΔPQR
PQ² = PR² = QR² = ar(ΔPAB)
PA² PB² AB² ar(ΔPQR)
PQ² = 1
PA² 2
PQ = 1
PA √2
PQ -1 = 1 - √2
PA √2
PQ-PA = 1 - √2
PA √2
AQ = 1 - √2
PQ √2
PQ = √2
AQ 1 - √2
_____________________________________________________________
★★★★ HOPE THIS HELPS YOU ★★★★
★★★★ PLS MARK ME AS BRAINLIEST ★★★★
Similar questions