in the triangle PQR, PQ = 6.4 mm, RQ = 4.8 mm and PO = 6 mm.
Р
6.4 mm
6 mm
R
O
4.8 mm
a. Find the area of triangle PQR.
b. Find the height corresponding to PQ.
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Answer:
Length of the 1st cross road parallel to the length = 70 m
Breadth of the 1st cross road parallel to the length = 5 m
Area of the 1st cross road = 70*5
= 350 sq m
Length of the 2nd cross road parallel to the breadth = 45 m
Breadth of the 2nd cross road parallel to the breadth = 5 m
Area of the 2nd cross road = 45*5
= 225 sq m
Area of the common part of the 2 cross roads with width 5 m that lies at the center of the rectangular park = 5*5
= 25 sq m
Area of the 2 cross roads = Area of the 1st cross road + Area of the 2nd cross road - Common area
⇒ (350 + 225) - 25
⇒ 575 - 25
= 550 sq m
Cost of constructing the roads = Rs. 105 sq m
Total cost of constructing the road = 550*105
= Rs. 57750
Step-by-step explanation:
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