Question

in the triangle , shown o is the centre of the circle , if angle OBC = 37 degree and angle BAC = x degree , what is the value of x​

Answer 1

Answer:

∠BOC=2∠BAC, the angle formed at the centre is twice the angle formed at the circumference.

Therefore, ∠BOC=2n

∠OCB=m

Since, OB = OC = radius of the circle = m

Thus, in Δ OBC, 

∠OCB+∠OBC+∠BOC=180∘

2m+2n=180

⇒m+n=90