Question

in the two units of company, the employees in unit one are 650 and monthly salary is 2750, the employees
in unit two are 700 & the monthly salary is 2500, then the combined arithmetic mean is​

Answer 1

Given:

Number of units in the company = 2

Number of employees in unit one = 650

Monthly salary  of the employees in unit one= 2750

Number of employees in unit two = 700

Monthly salary of the employees in unit two = 2500

To find:

• Combined arithmetic mean of the two units

Consideration:

• As the details of the salary are not mentioned, consider the given salary as one worker's monthly salary.
• Let the number of workers in unit one be $x$1 and the salary of a worker in unit one be $y$1.
• Let the number of workers in unit two be $x$2 and the salary of a worker in unit two be $y$2.

Formula to be used:

Required combined mean = $((x1 * y1) + (x2 * y2))/(x1 + y1)$

Solution:

• Unit one-

Number of workers in unit one = 650

Monthly salary of one worker in unit one = 2750

⇒Monthly salary of the 650 workers can be calculated by multiplying the number of workers with the salary on one worker. It is given by:

$= x1 * y1\\= 650 * 2750\\= 1787500$

• Unit two-

Number of workers in unit two = 700

Monthly salary of one worker in unit two = 2500

⇒Monthly salary of the 700 workers can be calculated by multiplying the number of workers with the salary of one worker, which is similar to the calculation done for unit one. It is given by:

$= x2 * y2\\= 700 * 2500\\= 1750000$

• Now, the combined arithmetic mean can be calculated using the formula mentioned above. To simplify the calculation, the monthly salary of all the workers in both units are calculated separately.

• Combined arithmetic mean is calculated as:

$= ((x1 * y1) + (x2 * y2)) / (x1 + y1)\\= (1787500 + 1750000) / (650+700)\\= 3537500 / 1350\\ = 2620.370$

∴ The required combined arithmetic mean = 2620.370

Hence, found.

Answer 2

Answer:

Step-by-step explanation: