Question

In the usual notation, the acceleration due to gravity at a height h from
the surface of the earth is
GM
(a) 8- (R+h)
(b) g = GM
VR+h
GM
(c) 8 = (R+h)
(d) g = GM (R+ h)​

Answer 1

The gravitational acceleration at height "h" is

g = GM/(R +h)^2

Explanation:

Force between two objects is given by the universal law of gravitation.

F = GMm/d^2

Here

• M = mass of the earth
• m = mass of the stone
• d = distance

F = mg

So

mg = GMm/d^2

Or

g = GM/d^2

Suppose the object is on the surface of the earth or nearby.

Now, in this case, d = R+ h

g = GM/(R +h)^2

Hence the gravitational acceleration at height "h" is g = GM/(R +h)^2.

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Answer 2

Answer:

(b) g = GM

VR+h

GM

Explanation: I have no explanation