In the vacation Gautam purchased (x2+8x-20) games CD while sanyam purchased (x+4)2 games CD
Who purchased more CD and how much
Answers
Answered by
135
gautam purchased game CD=x2+8x-20
=x2 +10x-2x-20
=x2 +(10-2)x+10×(-2)
=(x+10)(x-10)
put x=3
no. of cds=(3+10)×(3-2)=13×1=13cd
sanyam purchased game CD =(x +4)2
(x+4)(x+4)
put x=3
=(3+4)(3+4)
=7×7
=49CDs
sanyam purchased more CDS than gautam
》49-13=36CDS
=x2 +10x-2x-20
=x2 +(10-2)x+10×(-2)
=(x+10)(x-10)
put x=3
no. of cds=(3+10)×(3-2)=13×1=13cd
sanyam purchased game CD =(x +4)2
(x+4)(x+4)
put x=3
=(3+4)(3+4)
=7×7
=49CDs
sanyam purchased more CDS than gautam
》49-13=36CDS
Answered by
9
Answer:
sanyam purchased more CDs than gautam.
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