Question

In the volumetric analysis of NaOH against 0.05M H2C2O4.2H2O constant burette reading was found to be 9.8ML.the molarity of NaOH is a) 0.1020M b) 0.1120M c) 0.01200M d) 0.0980M

Answer 1

In the volumetric analysis of NaOH, the molarity of NaOH is found to be 0.1020 M

Given-

• Molarity of oxalic acid (H₂C₂O₄.2H₂O) is = 0.05 M

• Burette reading = 9.8 mL

By using the titrimetric analysis

M₁V₁ = M₂V₂

where M₁ is the molarity of oxalic acid

V₁ is the volume of oxalic acid taken in the conical flask.

M₂ is the molarity of NaOH

V₂ is the volume of NaOH consumed in the titration

Generally volume of oxalic acid taken in the conical flask is 20 mL.

By substituting the values we get

0.05 × 20 = M₂ × 9.8

M₂ = 0.1020 M

Answer 2

Explanation:

0.1020 mole is the correct answer for this question