In the xy-plane, the graph of the function f(x) = x2 + bx + 4 does not intersect the x-axis. Which of the following must be true about b?
Answers
Given info : In the xy-plane, the graph of the function f(x) = x² + bx + 4 does not intersect the x-axis.
To find : The value of b is ...
solution : a/c to question, f(x) = x² + bx + 4 doesn't intersect the x - axis. it means, quadratic function doesn't have real roots.
so Discriminant < 0
⇒b² - 4ac < 0
⇒(b)² - 4(1)(4) < 0
⇒b² - 16 < 0
⇒(b - 4)(b + 4) < 0
⇒-4 < b < 4
Therefore the value of b belongs to (-4, 4).
also read similar questions : if f(x)=ax+b/bx+a, prove that f(x).f(1/x)=1
https://brainly.in/question/32961571
The graph of the polynomial f(x) = ax² + bx + c is as shown in Fig. 2.20. Write the value of b² − 4ac and the number of ...
https://brainly.in/question/5911437
If x2+x-12 divides f x=x3+ax2+bx-84 exactly find a and b
https://brainly.in/question/3411846
Answer:
ljdjdjvjdjd hjdjsrgndsgxctvc kfjjchf