Question

In the xy-plane, the parabola with the equation y = (x + 4)2 intersects the line y = 36 at two points. What is the distance between those two points of intersection?

Answer 1

Step-by-step explanation:

First, set y = 25 equal to y = (x - 11)^2 and solve fo x. So, x ... Use the distance formula to find the distance between points A and B. The ... What is the equation of a line perpendicular to x-8y=7 and ( 0 ...

Answer 2

Answer:

12

Step-by-step explanation:

Given : y = ( x+4 )²

⇒ y= x² + 8x + 16

After substitute y=36. we get,

x² + 8x + 16 = 36

⇒ x² + 8x + 16 - 36 = 0

⇒ ( x² - 2x )  + ( 10x - 20 ) = 0

⇒ x ( x - 2 ) + 10 ( x - 2 ) = 0

⇒ ( x - 2 ) ( x + 10 ) = 0

⇒ x = 2 ; x = -10

∴ two points are  A,B are (2,36),(-10,36).

Distance between A and B is \

$\sqrt{(a1-a2)^{2} - (b1-b2)^{2} }$

⇒ $\sqrt{(2 -- 10^{2}- ( 36-36 )^{2} }$ = $\sqrt{12^{2} }$ = 12