In the xy-plane, the point (p,r) lies on the line with equation y=x+b, where b is a constant. The point with coordinates (2p,5r) lies on the line with equation y=2x+b. If p≠0, what is the value of rp? A) 25 B) 34 C) 43 D) 52
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Answer:
25
Step-by-step explanation:
ATQ
y=x+b (given)
r=p+b
r-p=b -------1
y=2x+b (given)
5r=4p+b
5r-4p=b -------2
equation 1 and 2 from pair of linear equation in two variable r and p . Solving eq. 1 and 2 , we get
r=-3b
p=-4b
Now, r÷p = -3b/-4b
= 3/4
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