Question

In the year 1924 a father was 3 times as old as his son, and in 1952 the father was 1whole1/3 times as old as his son. Find their ages in 1924. ​

Answer 1

Step-by-step explanation:

your answer is above if it is wrong I am sorry

Answer 2

Answer:

Step-by-step explanation:

1924- son= x
         father= 3x
1952- son= x+28
         father= 3x+28 = 4/3(x+28)
ATP

    3x + 28 = 4/3(x+28)

or, 3(3x+28) = 4(x+28)

or, 9x+84 = 4x+112