Math, asked by rkmurthy1644, 10 months ago

in the year 1950 Devraj age of six brothers is 15 years the youngest brother died in 1957 at the age of 12 years find the average of remaining Brothers in 1958 ​

Answers

Answered by topwriters
22

Average of remaining brothers in 1958 = 25 years

Step-by-step explanation:

Given: In the year 1950, average age of six brothers is 15 years.

Youngest brother died in 1957 at the age of 12 years.

Find: Average of remaining Brothers in 1958.​

Solution:

Let sum of ages of brothers be x.

In 1950, x/6 = 15

So x = 90

Youngest brother died in 1957 at the age of 12.

His age in 1950 would be 7 less than 12. Therefore 5 years.

Sum of remaining brothers in 1950 = 90 - 5 = 85.

All brothers would be 8 years more than what they were in 1950.

Sum of ages of remaining brothers in 1958 = 85 + (5 * 8) = 85 + 40 = 125

Average of remaining brothers in 1958 = 125 / 5 = 25 years.

Answered by sharanyalanka7
12

Step-by-step explanation:

refer to the above attachment

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