Question

in then given figure, AOB is a straight line. if, angle AOC = (3x-10)°, angle COD = 50° and angle BOD = (x+20)°,then find angle AOC with reason

Answer 1

Sum of all angles = 180
aoc+cod+bod = 180
3x-10+50+x+20 = 180
4x+60 = 180
4x = 120
x = 30
As AOC is 3x-10
3*30-10
90-10
80
Hope it helpa

Answer 2

Answer:

Concept:

linear pair:

When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. These are also referred to as additional angles.

Step-by-step explanation:

Given:

AOC = (3x-10)°

COD =  50°

BOD = (x+20)°

Find:

The angle AOC

Solution:

  $=(3 \mathrm{x}-10)^{\circ}+50^{\circ}+(\mathrm{x}+20)^{\circ}=180^{\circ}$   (linear pair)

  $\begin{aligned}&=3 x-10+50+x+20=180 \\&=4 x+60=180 \\&=4 x=180-60 \\&=4 x=120 \\&=x=120 / 4 \\&=x=30\end{aligned}$

The angle AOC is 30 degrees.

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