Question

in thermodynamic process 200j of heat given to gas and 100j of work done the change in internal energy is?

Answer 1

$dU=100\ J$ is the change in internal energy.

Explanation:

Given:

heat supplied to the system, $dQ=200\ J$

work done by the system of gas, $dW=100\ J$

Now according to the First law of thermodynamics the total heat interaction of the system is equal to the sum of total work done by the system and the change in internal energy.

$dQ=dW+dU$

where:

$dU=$ change in internal energy

$200=100+dU$

$dU=100\ J$

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TOPIC: First law of thermodynamics

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