In this adjoining figure, ABCD is a parallelogram. <BAC=60°
<ADC=70° FIND <ACD AND <ACB
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can you send a picture of diagram.?
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<BAC=60°=<ACD(ALTERNATIVE INTERIOR ANGLE)
<ADC=70°=<ABC(ALTERNATIVE INTERIOR ANGLE)
SO THIRD SIDE ANGLE WILL BE =50°<CAD AND <ACB
opposite side and angle would be same so we devide equally by bisecting it so three sides of two triangle would be same.
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