Question

in this below fig ABCD IS a cyclic quadrilateral O IS the centre of the circle if ANGLE BOD IS 160 find angle BPD​

Answer 1

Answer:

angle bpd is equal 100 degree

Step-by-step explanation:

angle bod is Central angle

angle Angle bod is inscribed in arc bcd

so,

angle angle bod = arc bcd

arc bcd = 160°

arc bad = 360-160

= 200°

angle bpd inscribed in arc bpd

point p is on circle

then,

angle bpd = 1/2 m( arc bad)

= 1/2 ×200

= 100

so,

angle bpd is 100 degree