In this circuit, when the current is falling at a steady rate of 1 a per 10 second, the reading of the voltmeter is found to be 1 volt. What is the value of the inductance?
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Ans: emf is generated by a source. where as voltage is just the potential difference between two points in a circuit.
AS we know that
emf=LΔi/Δtemf=LΔi/Δt
So just put values inductance and the rate of current in above equation .
emf=5(2)emf=5(2)
emf=10Vemf=10V
hope this answer helpful u
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