Question

In this [Co(OH2)6]2+ what is hybridisation of metal orbital

Answer 1

Answer:

$hello \: friend, \: I \: will \: tell \: you \: the \: simplest \: way \: to \: find \: out \: hybridisation \: of \: such \: compounds... \\ </strong></p><p></p><p><strong>[tex]hello \: friend, \: I \: will \: tell \: you \: the \: simplest \: way \: to \: find \: out \: hybridisation \: of \: such \: compounds... \\ 1.write \: down \: electronic \: configuration \: of \: Cobalt Co \\ </strong></p><p><strong>[tex]hello \: friend, \: I \: will \: tell \: you \: the \: simplest \: way \: to \: find \: out \: hybridisation \: of \: such \: compounds... \\ 1.write \: down \: electronic \: configuration \: of \: Cobalt Co \\ 2.write \: electronic \: configuration of of Oxygen and hydrogen separate \\ o = 1 {s}^{2} {2s}^{2} {2p}^{4} \\ h = {1s}^{1} \\ co =(ar) {3d}^{7} {4s}^{2} \\ terefore \: the \: rule \: is \: add \: the \: valence \: electron \: of \: oxygen \: and \: hydrogen \: and \: add \: last \: orbial \: electron \: of \: cobalt \: and \: subtract \: charge \: on \: the \: cimlex \: so... \\ we \: can \: wite \: this \: way......</strong></p><p></p><p><strong>[tex]hello \: friend, \: I \: will \: tell \: you \: the \: simplest \: way \: to \: find \: out \: hybridisation \: of \: such \: compounds... \\ 1.write \: down \: electronic \: configuration \: of \: Cobalt Co \\ 2.write \: electronic \: configuration of of Oxygen and hydrogen separate \\ o = 1 {s}^{2} {2s}^{2} {2p}^{4} \\ h = {1s}^{1} \\ co =(ar) {3d}^{7} {4s}^{2} \\ terefore \: the \: rule \: is \: add \: the \: valence \: electron \: of \: oxygen \: and \: hydrogen \: and \: add \: last \: orbial \: electron \: of \: cobalt \: and \: subtract \: charge \: on \: the \: cimlex \: so... \\ we \: can \: wite \: this \: way......$

Explanation:

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