Math, asked by utkarshsrivasta443, 6 months ago

In this fig. AB=AD.angleACB=95+angleBAC and angleBAD=150°.Find angleACB. ​

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Answered by monikasanda615
0

Answer:

170⁰

Step-by-step explanation:

AB= AD SO IT IS AN Isosceles triangle

x= 15⁰= ABD= ADB

BAC = DAC = 75⁰

ACB = 95⁰+ BAC

ACB = 95⁰+ 75⁰

ACB =170⁰

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