in this fig AD is median of /_\ ABC and M is the mid point of AD. BM is produced to AC at N. prove that AN = 1/3 AC
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Given in △ABC, AD is median BM and CN are perpendicular to AD form B and C respectively.
To prove:
BM=CN
Proof :
In △BMD and △CND
BD=CD (because AD is median)
∠M=∠N
∠BDM=∠CND (vertically opposite angles)
△BMD≅△CND
Therefore, BM=CN
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