Question

in this fig O is the centre of the circle find the value of x

Answer 1

Answer:

Step-by-step explanation:

Join OC

In Triangle OCA,

Angle OCA = 50 (ANGLES OPP. TO SIDE ARE EQUAL AND OA AND OC ARE RADII OF THE SAME CIRCLE)

SO BY ANGLE SUM PROPERTY, ANGLE COA = 80 DEGREES

NOW IN TRIANGLE OCB,

ANGLE OCB =20 DEGREES (ANGLES OPP. TO SIDE ARE EQUAL AND OB AND OC ARE RADII OF THE SAME CIRCLE)

SO BY ANGLE SUM PROPERTY,

ANGLE COB= 140 DEGREES

x= COMPLEX OF ANGLE AOB

ANGLE AOB = ANGLE AOC + ANGLE COB

=140+80

=220 DEGREES

SO, x = 220 degrees