In this figure, AB and CD are parallel. M is the mid point of BC. Prove that the area of ▵DCM and ▵BMN are equal?
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Given: AB and CD are parallel. M is the mid point of BC.
To Find : Prove that the area of ▵DCM and ▵BMN are equal
Solution:
AB and CD are parallels and BC is transversal
=> ∠MCD = ∠MBN alternate interior angles
CM = BM = BC/2 as M is mid point of BC
∠CMD = ∠BMN vertically opposite angles
=> ΔMCD ≅ΔMBN
Area of congruent triangles are equal
Hence area of ΔDCM = area of Δ BMN
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