Question

In this figure AB and CD intersect at O. If angle AOC + angle BOE = 70° , find angle BOE and reflex angle COE. ​

Answer 1

Explanation:

given:BOD=40°

AOC+BOE=70°

AOC=40° (vertically opposite angle)

AOC+BOE=70°

40°+BOE=70°

BOE=70°-40°=30°

COE=AB-(linear pair)AOC+BOE

=180°-40°+30°

=180°-70°

=110°

Answer 2

Answer:

‹BOE = 30° & REFLEX ANGLE = 250°

Explanation:

∠AOC + ∠BOE = 70°

∠AOC + ∠COE + ∠BOE = 180°

[ linear pair ]

So,

if ∠AOC + ∠BOE = 70°

so,

→ 70° + ∠COE = 180°

→ ∠COE = 180 - 70

→ ∠COE = 110°

.

∠BOD = ∠AOC [ Vertically Opposite Angles ]

.

Now,

→ ∠AOC + ∠COE + ∠BOE = 180°

→ 40° + 110° + ∠BOE = 180°

→ 150° + ∠BOE = 180°

→ ∠BOE = 180° - 150°

→ ∠BOE = 30°

.

∠BOD + ∠DOA = 180° [Liner Pair]

→ 40° + ∠DOA = 180°

→ ∠DOA = 180° - 40°

→ ∠DOA = 140°

Hence,

reflex angle ( ∠COE ) = ∠AOC + ∠DOE + ∠BOD + ∠BOE

reflex angle ( ∠COE ) = 40° + 140° + 40° + 30°

reflex angle ( ∠COE ) = 250°

HENCE, PROVED.

PLS MARK AS BRAINLIEST