in this figure AB || CD and EF is a transversal find the value of x in terms of q°
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Angle GHD= Angle AGH = q { alternate interior angles}
Angle GHD + Angle DHF = 180. { linear pair}
q + x= 180
x = 180-q
Angle GHD + Angle DHF = 180. { linear pair}
q + x= 180
x = 180-q
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Answer: ∠GHD = q (because alternate interior angles are equal)
now ∠x + ∠GHD =180°
x= 180° - ∠GHD = 180° - q (as q = ∠GHD)
alternate method
∠EGA = 180° - q
now ∠EGA = ∠x as the are alternate exterior angles
∠x = 180° - q
alternate method
∠BGH = 180°- q
now ∠BGH = x ( as they are corresponding angles, and corresponding angles are equal)
⇒ ∠x = 180°- q
hope this helps you
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