Question

in this figure ,AB is parallel to CD , angle ABF=60 degree and angle BFD = 35 degrees . calculate angle CDF​

Answer 1

Answer:

LET ANGLE CDF=X

angle BED =60°(A.I.A)

IN TRIANGLE (EDF)

35°+X=ANGLE (BED)................(EXTERIOR ANGLE PROPERTY)

X=60-35

X=25

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