Question

In this figure ABC IS A TRANGLE ∆ IN WHICH LABC >90° AND AD (perpendicular to) BC PRODUCED PROVE THAT. ✍
AC^2 = AB²+BC²-2BC.BD.
✍

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Answer 1

Answer:

Given: Triangle ABC obtuse angled at B. AD perpendicular to BC

To prove: AC^2=AB^2+BC^2+2BC. BD

Explanation:

The figure will be same as yours and u can find the proof in the attachment

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Answer 2

Answer:

Explanation:

Given

angle ABC>90^0

AD perpendicular BC

To prove

Ac^2=AB^2+BC^2+BC.BD

PROOF

Given below