In this figure Ac and BD are diagonal of kite ABCD with AB equal AD while AG and ME are the diagonal of rectangle AEGM. If AD equal to DG and BG is line segment find X minus Y
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In △ABM and △ADM
AB=AD (Given)
∠AMB=∠AMD[90°]
AM=AM [Common]
Therefore, △ABM≅△ADM [By SAS]
Hence, ∠ABM=∠ADM [By CPCT]
∠ADM=42°
∠ADM is exterior angle of △ADG and In △ADG AD=AG
Therefore ∠AGD=∠DAG=21°
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