in this figure AC > AB and AD bisects angle BAC prove that angle ADC > angle ADB
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I think this is how it is done
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given - Ac is greater than Ab and AD bisect angle BAC
to prove - ADC is greater than ADB
proof -- we know that when the side is big so its opposite angle is also big
so,
AC is greater than angle ADC is also greater
AB is smaller so the angle ADB is also smaller
Hence proved
Angle ADC is greater than ADB
to prove - ADC is greater than ADB
proof -- we know that when the side is big so its opposite angle is also big
so,
AC is greater than angle ADC is also greater
AB is smaller so the angle ADB is also smaller
Hence proved
Angle ADC is greater than ADB
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