Question

In this figure along side x:y=2:3 and ACD =130° Find x,y and z​

Answer 1

Answer:

x=52°, y=78° and z=50°

Step-by-step explanation:

Let the ratio be 2a and 3a.

2a+3a=130° (exterior angle=sum of two opposite interior angles)

5a=130°

a=26°

x=2a =2*26°=52°

y=3a=3*26°=78°

z+130°=180°(angles on a straight line)

z=180°-130°

z=50°

Answer 2

The values of x,y and z are 52, 78 and 50 respectively.

Step-by-step explanation:

Given information: x:y = 2:3 and ∠ACD = 130°.

Angle ACB and angle ACD are linear pairs it means they are supplementary angles.

$\angle ACB+\angle ACD=180$

$z+130=180$

$z=180-130$

$z=50$

It is given that x:y = 2:3.

Let x=2a and y=3a.

$\angle BAC+\angle ABC=\angle ACD$        (Exterior angle theorem)

$3a+2a=130$

$5a=130$

Divide both sides by 5.

$a=\frac{130}{5}$

$a=26$

$x=2(26)=52$

$y=3(26)=78$

Therefore, the values of x,y and z are 52, 78 and 50 respectively.

#Learn more

If x:y = 2:3, Angle ACD = 130 Degree , Find x​

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