in this figure an archery target marked with its five scoring areas from the centre outward as gold blue red black and white the diametre of the region representing gold score is 21 cm and each of the other bands is 10 cm wide . find the area of each of the five scoring region
Answers
According to the question....
The area of Gold region =
The area of Red region =
The area of Blue region =
ᴅɪᴀᴍᴇᴛᴇʀ ᴏꜰ ɢᴏʟᴅ ʀᴇɢɪᴏɴ= 21 ᴄᴍ
ᴛʜᴇɴ, ʀᴀᴅɪᴜꜱ ᴏꜰ ɢᴏʟᴅ ʀᴇɢɪᴏɴ =21/2 = 10.5 ᴄᴍ
The area of each of the five scoring regions.
ᴀʀᴇᴀ ᴏꜰ ɢᴏʟᴅ ʀᴇɢɪᴏɴ
= πʀ^2 = 22/7 (10.5)^2
= 22/7 x 110.25
= 346.5 ᴄᴍ ꜱq.
ʀᴀᴅɪᴜꜱ ꜰᴏʀ ɢᴏʟᴅ + ʀᴇᴅ ʀᴇɢɪᴏɴ
= 10.5 + 10.5
= 21 ᴄᴍ [ ʙʏ ɢɪᴠᴇɴ ᴄᴏɴᴅɪᴛɪᴏɴ ]
•°• ᴀʀᴇᴀ ꜰᴏʀ ʀᴇᴅ ʀᴇɢɪᴏɴ
= 22/7 [(21)^2 - (10.5)^2]
[ °•° ᴀʀᴇᴀ ᴏꜰ ᴀ ʀɪɴɢ = π (ʀ^2 - ʀ^2)
ᴡʜᴇʀᴇ, ʀ = ʀᴀᴅɪᴜꜱ ᴏꜰ ᴏᴜᴛᴇʀ ʀɪɴɢ, ᴀɴᴅ
ʀ = ʀᴀᴅɪᴜꜱ ᴏꜰ ɪɴɴᴇʀ ʀɪɴɢ.]
= 22/7 (21)^2 - 22/7 (10.5)^2
= 1386 - 346.5
= 1039.5 ᴄᴍ ꜱq.
ɴᴏᴡ, ʀᴀᴅɪᴜꜱ ꜰᴏʀ ɢᴏʟᴅ + ʀᴇᴅ + ʙʟᴜᴇ ʀᴇɢɪᴏɴ = 21 + 10.5 = 31.5 ᴄᴍ [ ʙʏ ɢɪᴠᴇɴ ᴄᴏɴᴅɪᴛɪᴏɴ ]
•°• ᴀʀᴇᴀ ꜰᴏʀ ʙʟᴜᴇ ʀᴇɢɪᴏɴ
= 22/7 [(31.5)^2 - (21)^2]
= 22/7 ( 31.5)^2 - 22/7(21)^2
= 3118.5 - 1386
= 1732.5 ᴄᴍ ꜱq.
ɴᴏᴡ, ʀᴀᴅɪᴜꜱ ꜰᴏʀ ɢᴏʟᴅ + ʀᴇᴅ + ʙʟᴜᴇ + ʙʟᴀᴄᴋ ʀᴇɢɪᴏɴ
= 31.5 + 10.5
= 42 ᴄᴍ [ ʙʏ ɢɪᴠᴇɴ ᴄᴏɴᴅɪᴛɪᴏɴ ]
•°• ᴀʀᴇᴀ ꜰᴏʀ ʙʟᴀᴄᴋ ʀᴇɢɪᴏɴ
= 22/7 [(42)^2 - (31.5)^2]
= 22/7 (42)^2 - 22/7 (31.5)^2
= 5544 - 3118.5
= 2425.5 ᴄᴍ ꜱq.
ʀᴀᴅɪᴜꜱ ꜰᴏʀ ɢᴏʟᴅ + ʀᴇᴅ + ʙʟᴜᴇ + ʙʟᴀᴄᴋ + ᴡʜɪᴛᴇ ʀᴇɢɪᴏɴ
= 42 + 10.5
= 52.5 ᴄᴍ [ ʙʏ ɢɪᴠᴇɴ ᴄᴏɴᴅɪᴛɪᴏɴ ]
•°• ᴀʀᴇᴀ ꜰᴏʀ ᴡʜɪᴛᴇ ʀᴇɢɪᴏɴ
= 22/7 [(52.5)^2 - (42)^2]
= 22/7 (52.5)^2 - 22/7 (42)^2
= 8662.5 - 5544
= 3118.5 ᴄᴍ ꜱq.
GOLD - 346.5 cm sq.
RED - 1039.5 cm sq.
BLUE - 1732.5 cm sq.
BLACK - 2425.5 cm sq.
WHITE - 3118.5 cm sq.