Question

In this
figure
CD is a
direct common
tangent to two circles intersecting
each other at A and B, then
AngleCAD + angleCBD = ?​

Answer 1

Answer:

Join AB.

Now, ∠ADC=∠ABD [Angle in the alternate segment]

∠ACD=∠ABC [Angle in the alternate segment]

In triangle CAD,

∠CAD+∠ADC+∠ACD=180

∘

[Angle sum property]

∠CAD+(∠ABD+∠ABC)=180

∘

∠CAD+∠CBD=180

∘

So, option D is the answer.