Question

In this figure 'Electrolysis of water',
observe the figure & answer the following
questions.
Test tube
Battery
Beaker
Did you see the gas bubbles forming near the
electrodes in the test tubes?
ii) Are these gases heavier or lighter than water?
iii) Are the volumes of the gases collected over
the solution in the two test tubes the same or
different?
iv) Which gas formed near the cathod?
v) Give chemical reactions of gas formed near
the cathod & anode.​

Answer 1

• The electrolysis of water produces hydrogen and oxygen gases. The electrolytic cell consists of a pair of platinum electrodes immersed in water to which a small amount of an electrolyte such as H2SO4 has been added. The electrolyte is necessary because pure water will not carry enough charge due to the lack of ions. At the anode, water is oxidized to oxygen gas and hydrogen ions. At the cathode, water is reduced to hydrogen gas and hydroxide ions.

• oxidation (anode):reduction (cathode):overall reaction:2H2O(l)→O2(g)+4H+(aq)+4e−2H2O(l)+2e−→H2(g)+2OH−(aq)2H2O(l)→O2(g)+2H2(g)E0=−1.23VE0=−0.83VE0cell=−2.06V(23.9.1)
• In order to obtain the overall reaction, the reduction half-reaction was multiplied by two to equalize the electrons. The hydrogen ion and hydroxide ions produced in each reaction combine to form water. The H2SO4 is not consumed in the reaction
• hope it helps u
• keep calm and u can do it