Question

in this figure given below find <z

(I) 40° (ii) 110° (iii) 45° (iv) none​

Answer 1

Step-by-step explanation:

z=45°

AB= AD (given)

angle ABD= angle ADB( angles opposite to equal sides of a triangle are equal )

Angle ABE + angle ABD = 180° (linear pair)

110+ ABD = 180

ABD = ADB = 70°

now,

angle ADB = z + angle ACD( exterior angle of a triangle property)

70= z + 25

z = 70-25

z = 45°

HOPE IT HELPS

Answer 2

Step-by-step explanation:

110+ABD=180°

ABD=ADB=70

70=Z+25

Z=70-25

Z=45°