Question

in this figure, given PE=RE and angle a =angle b prove that BP=AR​

Answer 1

Answer:

BP=AR proved using congruence of triangle

Step-by-step explanation:

Given: PE=RE; ∠a=∠b

To prove: BP=AR

Construction: Join RP

Proof:

In ΔBRP and ΔAPR

∠RBP=∠PAR (given i.e ∠b=∠a)

∠BRP=∠APR (angles opposite to equal sides are equal ∵ RE=PE)

RP=PR(common)

So, ΔBRP≅ΔAPR (by AAS)

∴ BP=AR (by cpct)

Hence proved.