Question

In this figure , if AOB = 90° , AC = BC , OA=10 cm and OC =13 cm . The area of AOB is​

Answer 1

Step-by-step explanation:

Given ∠AOB=90

∘

,AC=BC,OA=10cm,OC=13cm

Since AC=BC, C is the midpoint of AB

In right angled triangle the mid-point of the hypotenuse is equidistant from the vertices.

∴OC=CA=CB

⇒AC=CB=13cm

⇒AB=AC+CB=13+13=26cm

In right triangle AOB, (AB)

2

=(OA)

2

+(OB)

2