Question

In this figure. O is the centre of the circle and angleBOA = 120°. then find the value of x.​

Answer 1

angle BOA = 120 (given)

angle OAC = 60 (LINEAR PAIR )

In triangle OAC,

OA = OC (Radii of same circle )

angleOAC = angleOCA = x

(angle opposite to equal sides are equal )

angleA + angleO + angleC = 180

x + x + 60 = 180

2x = 120

x =60

Answer 2

$\large{\implies{Answer}}$

120+Angle(AOC)=180 (Linear pair)

Angle(AOC)=180-120=60degree

Angle (O)=angle(C)

60degree=angle(C)

A+O+C=180 (angle sum property )

x+60+60=180

x+120=180

✏x=180-120=60degree