In this figure, OAQB is a quadrant of a circle
of radius 7 cm and APB is a semicircle. Find
the area of the shaded region.
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in right angled triangle AOB,
(AB)^2=(AO)^2+(OB)^2
AB^2=(7)^2+(7)^2
AB^2=49+49
AB^2=98
AB=9.89(approx)
R=AB/2
R=9.89/2
R=4.945
area of shaded region = area of semicircle ABP - area of quadrant OAQB
=πR- πR*1/4
=πR(1-1/4)
=22/7*4.945(3/4)
=15.54(approx)(0.75)
=11.655 sq.cm
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