in this figure PQ || BA and RS || CA. If BP = RC prove that RS = CQ
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Answer:
PQ∣∣BA,RS∣∣CA
BP=RC
To prove:
(i) △BSR≅△PQC
(ii) RS=CQ
Proof: BP=RC
BC−RC=BC−BP
BR=PC
Now, in △BSR and △PQC
∠B=∠P (Corresponding angles)
∠R=∠C (Corresponding angles)
BR=PC (Proved)
△BSR≅△PQC
BS=PQ
RS=CQ
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