in this figure shown if PA=2,PB=5,PD=10,then PC is:
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the length of pc would be 4
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Since secants AB and CD are secants
And they meet at an external point P
So, PA*PB=PC*PD
=>2*5=PC*10
=>PC=2*5/10
=>PC=10/10
=>PC=1
And they meet at an external point P
So, PA*PB=PC*PD
=>2*5=PC*10
=>PC=2*5/10
=>PC=10/10
=>PC=1
angel84:
what would be the answer 1 or 4
my bad the answer is one. sorry
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