Question

in this formula of resultant vector put A=B=a
and find out the values for the following-

(i)angle=0 degree
(ii) angle=60 degree
(iii) angle=90 degree
(iv) angle =120 degree
(v) angle =180 degree
​

Answer 1

Answer:

or , AC = AB cosθ

or , AC = OD cosθ

= Q cosθ [ AB = OD = Q ]

or , BC = AB sinθ

or , BC = OD sinθ

= Q sinθ [ AB = OD = Q }

R = P2+2PQcosθ+Q2.

Let ϕ be the angle made by resultant R with P .

Answer 2

Answer:

Answer:

Hiii,

so, we can write the formula as

2acos theta /2

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now, if theta =0 ,than

2acos0/2

=2acos 0°

=2a

because cos0°=1

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if theta =60°

2acos60/2

=2acos30°

=2a×√3/2

=√3a

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if theta=90°

2acos90/2

=2acos45°

=2a×1/√2

=√2a

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if theta=120

2acos120/2

=2acos60°

=2a×1/2

=a.

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if theta= 180

=2acos180/2

=2acos90°

= 0

because cos90°= 0& if we multiply any number by 0 than the result will be 0

#Hope it will help you

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