in this how many more festival names are left plz tell fast guys
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Answered by
2
Answer:
AgCl⇌Ag
+
+Cl
−
a 0 0
a-S S S+0.1
k
sp
=1.6×10
−10
=[Ag
+
][Cl
−
]
=S(0.1+S)
k
sp
is value seems to be very small
S value can be ignored, with respect to 0.1 M
1.6×10
−10
=S×0.1
S=1.6×10
−9
M
Answered by
1
Answer:
2 festival arw leftin this because the year is end
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