Question

in this quadratic - > 25x^2+25x-6=0
... Ans by factorization method is - 6/5&1/5 taking 30&5 as factor.... But by applying quadratic formula (in img) i m getting - 2/5&-3/5 which is wrong.... Please tell me my mistake।
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Answer 1

Factorization method:

Given Equation is 25x^2  + 25x - 6 = 0

25x^2 - 5x + 30x - 6 = 0

5x(5x - 1) + 6(5x - 1) = 0

(5x + 6)(5x - 1) = 0

5x + 6 = 0, 5x - 1 = 0

x = -6/5,1/5.


Quadratic Equation:

(a) 

$\frac{ - b + \sqrt{b^2 - 4ac} }{2a}$

$\frac{-25 + \sqrt{25^2 - 4 * 25 * (-6)} }{2 * 25}$

$\frac{ -25 + \sqrt{625 + 600} }{50}$

$\frac{-25 + \sqrt{1225} }{50}$

$\frac{-25 + 35}{50}$

$\frac{10}{50}$

$\frac{1}{5}$



(b)

$\frac{-b - \sqrt{b^2 - 4ac} }{2a}$

$\frac{-25 - \sqrt{(25)^2 - 4 * 25 * (-6)} }{2 * 25}$

$\frac{-25 - \sqrt{625 + 600} }{50}$

$\frac{-25 - \sqrt{1225} }{50}$

$\frac{-25 - 35}{50}$

$\frac{-60}{50}$

$\frac{-6}{5}$



Therefore the solutions of the equations are $\frac{-6}{5}, \frac{1}{5}$


Hope this helps!

Answer 2

Hi,

Please see the attached file !


Thanks