CBSE BOARD X, asked by 118usharani28, 9 months ago

In this question Find graphically the vertices of the triangle whose sides have the equation 2y–x=8, 5y–x=14, 2x–y= –1 I have done all steps correct and the graph was also correct but my final awnser was half wrong then how much marks will i get out of 3 This was the question of cbse exam 2020

Answers

Answered by divya159617
0

Answer:

Sorry don't know..

Answered by k047
2

2y - x = 8

2y = 8 + x

y = 8 + x / 2

                   Sub x = 0

y = 8 + 0 / 2

y = 4

5y - x = 14

5y = 14 + x

y = 14 + x / 5

                        Sub x = 1

y = 14 + 1 / 5

y = 3

2x - y = 1

2x = 1 + y

x = 1 + y / 2

                            Sub y = 1

x = 1 + 1 / 2

x = 2

Therefore, the vertices of the triangle are (0,4) ; (1,3) ; (1,2).

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